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7r^2+5=166
We move all terms to the left:
7r^2+5-(166)=0
We add all the numbers together, and all the variables
7r^2-161=0
a = 7; b = 0; c = -161;
Δ = b2-4ac
Δ = 02-4·7·(-161)
Δ = 4508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4508}=\sqrt{196*23}=\sqrt{196}*\sqrt{23}=14\sqrt{23}$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{23}}{2*7}=\frac{0-14\sqrt{23}}{14} =-\frac{14\sqrt{23}}{14} =-\sqrt{23} $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{23}}{2*7}=\frac{0+14\sqrt{23}}{14} =\frac{14\sqrt{23}}{14} =\sqrt{23} $
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