(2x-12)=(9x-26)=(4x+43)

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Solution for (2x-12)=(9x-26)=(4x+43) equation: 



(2x-12)=(9x-26)=(4x+43)

We move all terms to the left:

(2x-12)-((9x-26))=0

We get rid of parentheses

2x-((9x-26))-12=0



We calculate terms in parentheses: -((9x-26)), so:

(9x-26)

We get rid of parentheses

9x-26

Back to the equation:

-(9x-26)



We get rid of parentheses

2x-9x+26-12=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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