7p-4(1+7p)=122

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Solution for 7p-4(1+7p)=122 equation: 



7p-4(1+7p)=122

We move all terms to the left:

7p-4(1+7p)-(122)=0

We add all the numbers together, and all the variables

7p-4(7p+1)-122=0

We multiply parentheses

7p-28p-4-122=0

We add all the numbers together, and all the variables

-21p-126=0

We move all terms containing p to the left, all other terms to the right

-21p=126

p=126/-21

p=-6

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