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7p^2-24p-16=0
a = 7; b = -24; c = -16;
Δ = b2-4ac
Δ = -242-4·7·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-32}{2*7}=\frac{-8}{14} =-4/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+32}{2*7}=\frac{56}{14} =4 $
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