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7n^2=448
We move all terms to the left:
7n^2-(448)=0
a = 7; b = 0; c = -448;
Δ = b2-4ac
Δ = 02-4·7·(-448)
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12544}=112$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-112}{2*7}=\frac{-112}{14} =-8 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+112}{2*7}=\frac{112}{14} =8 $
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