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3(4x-2)-4=2(3x-4)
We move all terms to the left:
3(4x-2)-4-(2(3x-4))=0
We multiply parentheses
12x-(2(3x-4))-6-4=0
We calculate terms in parentheses: -(2(3x-4)), so:We add all the numbers together, and all the variables
2(3x-4)
We multiply parentheses
6x-8
Back to the equation:
-(6x-8)
12x-(6x-8)-10=0
We get rid of parentheses
12x-6x+8-10=0
We add all the numbers together, and all the variables
6x-2=0
We move all terms containing x to the left, all other terms to the right
6x=2
x=2/6
x=1/3
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