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7n^2-53n-18=0
a = 7; b = -53; c = -18;
Δ = b2-4ac
Δ = -532-4·7·(-18)
Δ = 3313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{3313}}{2*7}=\frac{53-\sqrt{3313}}{14} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{3313}}{2*7}=\frac{53+\sqrt{3313}}{14} $
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