6(y-2)+2=(3y+5)

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Solution for 6(y-2)+2=(3y+5) equation: 



6(y-2)+2=(3y+5)

We move all terms to the left:

6(y-2)+2-((3y+5))=0

We multiply parentheses

6y-((3y+5))-12+2=0



We calculate terms in parentheses: -((3y+5)), so:

(3y+5)

We get rid of parentheses

3y+5

Back to the equation:

-(3y+5)



We add all the numbers together, and all the variables

6y-(3y+5)-10=0

We get rid of parentheses

6y-3y-5-10=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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