7k2-3=455

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Solution for 7k2-3=455 equation:



7k^2-3=455
We move all terms to the left:
7k^2-3-(455)=0
We add all the numbers together, and all the variables
7k^2-458=0
a = 7; b = 0; c = -458;
Δ = b2-4ac
Δ = 02-4·7·(-458)
Δ = 12824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{12824}=\sqrt{4*3206}=\sqrt{4}*\sqrt{3206}=2\sqrt{3206}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{3206}}{2*7}=\frac{0-2\sqrt{3206}}{14} =-\frac{2\sqrt{3206}}{14} =-\frac{\sqrt{3206}}{7} $
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{3206}}{2*7}=\frac{0+2\sqrt{3206}}{14} =\frac{2\sqrt{3206}}{14} =\frac{\sqrt{3206}}{7} $

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