22-2(4-x)=(7-3x)*(-10)

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Solution for 22-2(4-x)=(7-3x)*(-10) equation: 



22-2(4-x)=(7-3x)(-10)

We move all terms to the left:

22-2(4-x)-((7-3x)(-10))=0

We add all the numbers together, and all the variables

-2(-1x+4)-((-3x+7)(-10))+22=0

We multiply parentheses

2x-((-3x+7)(-10))-8+22=0

We multiply parentheses ..

2x-((+30x-70))-8+22=0



We calculate terms in parentheses: -((+30x-70)), so:

(+30x-70)

We add all the numbers together, and all the variables

(30x-70)

We get rid of parentheses

30x-70

Back to the equation:

-(30x-70)



We add all the numbers together, and all the variables

2x-(30x-70)+14=0

We get rid of parentheses

2x-30x+70+14=0

We add all the numbers together, and all the variables

-28x+84=0

We move all terms containing x to the left, all other terms to the right

-28x=-84

x=-84/-28

x=+3

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