7c+2(c-2)=4(3c-1)

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Solution for 7c+2(c-2)=4(3c-1) equation: 



7c+2(c-2)=4(3c-1)

We move all terms to the left:

7c+2(c-2)-(4(3c-1))=0

We multiply parentheses

7c+2c-(4(3c-1))-4=0



We calculate terms in parentheses: -(4(3c-1)), so:

4(3c-1)

We multiply parentheses

12c-4

Back to the equation:

-(12c-4)



We add all the numbers together, and all the variables

9c-(12c-4)-4=0

We get rid of parentheses

9c-12c+4-4=0

We add all the numbers together, and all the variables

-3c=0

c=0/-3

c=0

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