2m+m-3m+2m+4m=12

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Solution for 2m+m-3m+2m+4m=12 equation: 



2m+m-3m+2m+4m=12

We move all terms to the left:

2m+m-3m+2m+4m-(12)=0

We add all the numbers together, and all the variables

6m-12=0

We move all terms containing m to the left, all other terms to the right

6m=12

m=12/6

m=2

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