7c+2(2c-15)=6

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Solution for 7c+2(2c-15)=6 equation: 



7c+2(2c-15)=6

We move all terms to the left:

7c+2(2c-15)-(6)=0

We multiply parentheses

7c+4c-30-6=0

We add all the numbers together, and all the variables

11c-36=0

We move all terms containing c to the left, all other terms to the right

11c=36

c=36/11

c=3+3/11

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