7b+3=3-3(b+4)

Solution for 7b+3=3-3(b+4) equation:

7b+3=3-3(b+4)

We move all terms to the left:

7b+3-(3-3(b+4))=0


We calculate terms in parentheses: -(3-3(b+4)), so:

3-3(b+4)

determiningTheFunctionDomain
-3(b+4)+3

We multiply parentheses

-3b-12+3

We add all the numbers together, and all the variables

-3b-9

Back to the equation:

-(-3b-9)


We get rid of parentheses

7b+3b+9+3=0

We add all the numbers together, and all the variables

10b+12=0

We move all terms containing b to the left, all other terms to the right

10b=-12

b=-12/10

b=-1+1/5