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x.10(4x+4)=400
We move all terms to the left:
x.10(4x+4)-(400)=0
We multiply parentheses
4x^2+4x-400=0
a = 4; b = 4; c = -400;
Δ = b2-4ac
Δ = 42-4·4·(-400)
Δ = 6416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{6416}=\sqrt{16*401}=\sqrt{16}*\sqrt{401}=4\sqrt{401}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{401}}{2*4}=\frac{-4-4\sqrt{401}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{401}}{2*4}=\frac{-4+4\sqrt{401}}{8} $
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