7=3(z+2)-2

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Solution for 7=3(z+2)-2 equation: 



7=3(z+2)-2

We move all terms to the left:

7-(3(z+2)-2)=0



We calculate terms in parentheses: -(3(z+2)-2), so:

3(z+2)-2

We multiply parentheses

3z+6-2

We add all the numbers together, and all the variables

3z+4

Back to the equation:

-(3z+4)



We get rid of parentheses

-3z-4+7=0

We add all the numbers together, and all the variables

-3z+3=0

We move all terms containing z to the left, all other terms to the right

-3z=-3

z=-3/-3

z=1

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