4y-5(3y+5)=-1-5(-3-y)

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Solution for 4y-5(3y+5)=-1-5(-3-y) equation: 



4y-5(3y+5)=-1-5(-3-y)

We move all terms to the left:

4y-5(3y+5)-(-1-5(-3-y))=0

We add all the numbers together, and all the variables

4y-5(3y+5)-(-1-5(-1y-3))=0

We multiply parentheses

4y-15y-(-1-5(-1y-3))-25=0



We calculate terms in parentheses: -(-1-5(-1y-3)), so:

-1-5(-1y-3)

determiningTheFunctionDomain
-5(-1y-3)-1

We multiply parentheses

5y+15-1

We add all the numbers together, and all the variables

5y+14

Back to the equation:

-(5y+14)



We add all the numbers together, and all the variables

-11y-(5y+14)-25=0

We get rid of parentheses

-11y-5y-14-25=0

We add all the numbers together, and all the variables

-16y-39=0

We move all terms containing y to the left, all other terms to the right

-16y=39

y=39/-16

y=-2+7/16

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