-2(t-3)+4=2(t+1)

Solution for -2(t-3)+4=2(t+1) equation:

-2(t-3)+4=2(t+1)

We move all terms to the left:

-2(t-3)+4-(2(t+1))=0

We multiply parentheses

-2t-(2(t+1))+6+4=0


We calculate terms in parentheses: -(2(t+1)), so:

2(t+1)

We multiply parentheses

2t+2

Back to the equation:

-(2t+2)


We add all the numbers together, and all the variables

-2t-(2t+2)+10=0

We get rid of parentheses

-2t-2t-2+10=0

We add all the numbers together, and all the variables

-4t+8=0

We move all terms containing t to the left, all other terms to the right

-4t=-8

t=-8/-4

t=+2