7=-10/3(-9)+b

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Solution for 7=-10/3(-9)+b equation: 



7=-10/3(-9)+b

We move all terms to the left:

7-(-10/3(-9)+b)=0



Domain of the equation: 3(-9)+b)!=0

b∈R



We multiply all the terms by the denominator


-(-10+7*3(-9)+b)=0



We calculate terms in parentheses: -(-10+7*3(-9)+b), so:

-10+7*3(-9)+b

determiningTheFunctionDomain
b-10+7*3(-9)

We add all the numbers together, and all the variables

b-199

Back to the equation:

-(b-199)



We get rid of parentheses

-b+199=0

We add all the numbers together, and all the variables

-1b+199=0

We move all terms containing b to the left, all other terms to the right

-b=-199

b=-199/-1

b=+199

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