5x-(x+3)=(1/3)(9x+18)-5

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Solution for 5x-(x+3)=(1/3)(9x+18)-5 equation: 



5x-(x+3)=(1/3)(9x+18)-5

We move all terms to the left:

5x-(x+3)-((1/3)(9x+18)-5)=0



Domain of the equation: 3)(9x+18)-5)!=0

x∈R



We add all the numbers together, and all the variables

5x-(x+3)-((+1/3)(9x+18)-5)=0

We get rid of parentheses

5x-x-((+1/3)(9x+18)-5)-3=0

We multiply parentheses ..

-((+9x^2+1/3*18)-5)+5x-x-3=0

We multiply all the terms by the denominator


-((+9x^2+1+5x*3*18)-5)-x*3*18)-5)-3*3*18)-5)=0



We calculate terms in parentheses: -((+9x^2+1+5x*3*18)-5), so:

(+9x^2+1+5x*3*18)-5

We get rid of parentheses

9x^2+5x*3*18+1-5

We add all the numbers together, and all the variables

9x^2+5x*3*18-4

Wy multiply elements

9x^2+270x*1-4

Wy multiply elements

9x^2+270x-4

Back to the equation:

-(9x^2+270x-4)



Wy multiply elements

-2916x^3*1-(9x^2+270x-4)=0

We get rid of parentheses

-2916x^3*1-9x^2-270x+4=0

We do not support expression: x^3

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