78+9y=2(5y+8)+2(3y+3)

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Solution for 78+9y=2(5y+8)+2(3y+3) equation: 



78+9y=2(5y+8)+2(3y+3)

We move all terms to the left:

78+9y-(2(5y+8)+2(3y+3))=0



We calculate terms in parentheses: -(2(5y+8)+2(3y+3)), so:

2(5y+8)+2(3y+3)

We multiply parentheses

10y+6y+16+6

We add all the numbers together, and all the variables

16y+22

Back to the equation:

-(16y+22)



We get rid of parentheses

9y-16y-22+78=0

We add all the numbers together, and all the variables

-7y+56=0

We move all terms containing y to the left, all other terms to the right

-7y=-56

y=-56/-7

y=+8

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