(x+5)(x+5)=(x-1)(x+3)-4

Solution for (x+5)(x+5)=(x-1)(x+3)-4 equation:

(x+5)(x+5)=(x-1)(x+3)-4

We move all terms to the left:

(x+5)(x+5)-((x-1)(x+3)-4)=0

We multiply parentheses ..

(+x^2+5x+5x+25)-((x-1)(x+3)-4)=0


We calculate terms in parentheses: -((x-1)(x+3)-4), so:

(x-1)(x+3)-4

We multiply parentheses ..

(+x^2+3x-1x-3)-4

We get rid of parentheses

x^2+3x-1x-3-4

We add all the numbers together, and all the variables

x^2+2x-7

Back to the equation:

-(x^2+2x-7)


We get rid of parentheses

x^2-x^2+5x+5x-2x+25+7=0

We add all the numbers together, and all the variables

8x+32=0

We move all terms containing x to the left, all other terms to the right

8x=-32

x=-32/8

x=-4