4x-2(1x)=2(3x-2)

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Solution for 4x-2(1x)=2(3x-2) equation: 



4x-2(1x)=2(3x-2)

We move all terms to the left:

4x-2(1x)-(2(3x-2))=0

We add all the numbers together, and all the variables

-17x-(2(3x-2))=0



We calculate terms in parentheses: -(2(3x-2)), so:

2(3x-2)

We multiply parentheses

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

-17x-6x+4=0

We add all the numbers together, and all the variables

-23x+4=0

We move all terms containing x to the left, all other terms to the right

-23x=-4

x=-4/-23

x=4/23

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