2(3x+2)=-4(2x-4)+3x

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Solution for 2(3x+2)=-4(2x-4)+3x equation: 



2(3x+2)=-4(2x-4)+3x

We move all terms to the left:

2(3x+2)-(-4(2x-4)+3x)=0

We multiply parentheses

6x-(-4(2x-4)+3x)+4=0



We calculate terms in parentheses: -(-4(2x-4)+3x), so:

-4(2x-4)+3x

We add all the numbers together, and all the variables

3x-4(2x-4)

We multiply parentheses

3x-8x+16

We add all the numbers together, and all the variables

-5x+16

Back to the equation:

-(-5x+16)



We get rid of parentheses

6x+5x-16+4=0

We add all the numbers together, and all the variables

11x-12=0

We move all terms containing x to the left, all other terms to the right

11x=12

x=12/11

x=1+1/11

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