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73=2(2x+5)-2(x-5)
We move all terms to the left:
73-(2(2x+5)-2(x-5))=0
We calculate terms in parentheses: -(2(2x+5)-2(x-5)), so:We get rid of parentheses
2(2x+5)-2(x-5)
We multiply parentheses
4x-2x+10+10
We add all the numbers together, and all the variables
2x+20
Back to the equation:
-(2x+20)
-2x-20+73=0
We add all the numbers together, and all the variables
-2x+53=0
We move all terms containing x to the left, all other terms to the right
-2x=-53
x=-53/-2
x=26+1/2
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