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(2x-6)4x=360
We move all terms to the left:
(2x-6)4x-(360)=0
We multiply parentheses
8x^2-24x-360=0
a = 8; b = -24; c = -360;
Δ = b2-4ac
Δ = -242-4·8·(-360)
Δ = 12096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12096}=\sqrt{576*21}=\sqrt{576}*\sqrt{21}=24\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24\sqrt{21}}{2*8}=\frac{24-24\sqrt{21}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24\sqrt{21}}{2*8}=\frac{24+24\sqrt{21}}{16} $
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