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72=6p^2
We move all terms to the left:
72-(6p^2)=0
a = -6; b = 0; c = +72;
Δ = b2-4ac
Δ = 02-4·(-6)·72
Δ = 1728
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1728}=\sqrt{576*3}=\sqrt{576}*\sqrt{3}=24\sqrt{3}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{3}}{2*-6}=\frac{0-24\sqrt{3}}{-12} =-\frac{24\sqrt{3}}{-12} =-\frac{2\sqrt{3}}{-1} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{3}}{2*-6}=\frac{0+24\sqrt{3}}{-12} =\frac{24\sqrt{3}}{-12} =\frac{2\sqrt{3}}{-1} $
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