72=2x(2)+2x

Solution for 72=2x(2)+2x equation:

72=2x(2)+2x

We move all terms to the left:

72-(2x(2)+2x)=0

We add all the numbers together, and all the variables

-(+2x^2+2x)+72=0

We get rid of parentheses

-2x^2-2x+72=0

a = -2; b = -2; c = +72;
Δ = b2-4ac
Δ = -22-4·(-2)·72
Δ = 580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{580}=\sqrt{4*145}=\sqrt{4}*\sqrt{145}=2\sqrt{145}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{145}}{2*-2}=\frac{2-2\sqrt{145}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{145}}{2*-2}=\frac{2+2\sqrt{145}}{-4}
$