8+x=2(1/2x+4)

Solution for 8+x=2(1/2x+4) equation:

8+x=2(1/2x+4)

We move all terms to the left:

8+x-(2(1/2x+4))=0


Domain of the equation: 2x+4))!=0

x∈R


We multiply all the terms by the denominator


x*2x+8*2x+4))-(2(1+4))=0

We add all the numbers together, and all the variables

x*2x+8*2x+4))-(25)=0

We add all the numbers together, and all the variables

x*2x+8*2x=0

Wy multiply elements

2x^2+16x=0

a = 2; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·2·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*2}=\frac{0}{4}
=0
$