72=(1)/(2)(2h+2)*(h)

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Solution for 72=(1)/(2)(2h+2)*(h) equation: 



72=(1)/(2)(2h+2)(h)

We move all terms to the left:

72-((1)/(2)(2h+2)(h))=0



Domain of the equation: 2(2h+2)h)!=0

h∈R



We multiply all the terms by the denominator


-(1+72*2(2h+2)h)=0



We calculate terms in parentheses: -(1+72*2(2h+2)h), so:

1+72*2(2h+2)h

determiningTheFunctionDomain
72*2(2h+2)h+1

Wy multiply elements

144h(2+1

Back to the equation:

-(144h(2+1)



We add all the numbers together, and all the variables

-(144h3=0

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