71x-2=(51x+4)+17x

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Solution for 71x-2=(51x+4)+17x equation: 



71x-2=(51x+4)+17x

We move all terms to the left:

71x-2-((51x+4)+17x)=0



We calculate terms in parentheses: -((51x+4)+17x), so:

(51x+4)+17x

We add all the numbers together, and all the variables

17x+(51x+4)

We get rid of parentheses

17x+51x+4

We add all the numbers together, and all the variables

68x+4

Back to the equation:

-(68x+4)



We get rid of parentheses

71x-68x-4-2=0

We add all the numbers together, and all the variables

3x-6=0

We move all terms containing x to the left, all other terms to the right

3x=6

x=6/3

x=2

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