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-4x+6x-6=2(x-4)-2
We move all terms to the left:
-4x+6x-6-(2(x-4)-2)=0
We add all the numbers together, and all the variables
2x-(2(x-4)-2)-6=0
We calculate terms in parentheses: -(2(x-4)-2), so:We get rid of parentheses
2(x-4)-2
We multiply parentheses
2x-8-2
We add all the numbers together, and all the variables
2x-10
Back to the equation:
-(2x-10)
2x-2x+10-6=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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