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11-4(x-2)=3(x+1)+2
We move all terms to the left:
11-4(x-2)-(3(x+1)+2)=0
We multiply parentheses
-4x-(3(x+1)+2)+8+11=0
We calculate terms in parentheses: -(3(x+1)+2), so:We add all the numbers together, and all the variables
3(x+1)+2
We multiply parentheses
3x+3+2
We add all the numbers together, and all the variables
3x+5
Back to the equation:
-(3x+5)
-4x-(3x+5)+19=0
We get rid of parentheses
-4x-3x-5+19=0
We add all the numbers together, and all the variables
-7x+14=0
We move all terms containing x to the left, all other terms to the right
-7x=-14
x=-14/-7
x=+2
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