71=4(x+3)+3(x+8)

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Solution for 71=4(x+3)+3(x+8) equation: 



71=4(x+3)+3(x+8)

We move all terms to the left:

71-(4(x+3)+3(x+8))=0



We calculate terms in parentheses: -(4(x+3)+3(x+8)), so:

4(x+3)+3(x+8)

We multiply parentheses

4x+3x+12+24

We add all the numbers together, and all the variables

7x+36

Back to the equation:

-(7x+36)



We get rid of parentheses

-7x-36+71=0

We add all the numbers together, and all the variables

-7x+35=0

We move all terms containing x to the left, all other terms to the right

-7x=-35

x=-35/-7

x=+5

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