33=7(4+7b)+5(1+4b)

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Solution for 33=7(4+7b)+5(1+4b) equation: 



33=7(4+7b)+5(1+4b)

We move all terms to the left:

33-(7(4+7b)+5(1+4b))=0

We add all the numbers together, and all the variables

-(7(7b+4)+5(4b+1))+33=0



We calculate terms in parentheses: -(7(7b+4)+5(4b+1)), so:

7(7b+4)+5(4b+1)

We multiply parentheses

49b+20b+28+5

We add all the numbers together, and all the variables

69b+33

Back to the equation:

-(69b+33)



We get rid of parentheses

-69b-33+33=0

We add all the numbers together, and all the variables

-69b=0

b=0/-69

b=0

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