71=3f+(f-9)+f

Solution for 71=3f+(f-9)+f equation:

71=3f+(f-9)+f

We move all terms to the left:

71-(3f+(f-9)+f)=0


We calculate terms in parentheses: -(3f+(f-9)+f), so:

3f+(f-9)+f

We add all the numbers together, and all the variables

4f+(f-9)

We get rid of parentheses

4f+f-9

We add all the numbers together, and all the variables

5f-9

Back to the equation:

-(5f-9)


We get rid of parentheses

-5f+9+71=0

We add all the numbers together, and all the variables

-5f+80=0

We move all terms containing f to the left, all other terms to the right

-5f=-80

f=-80/-5

f=+16