73=3x+(x+3)+(4x-2)

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Solution for 73=3x+(x+3)+(4x-2) equation: 



73=3x+(x+3)+(4x-2)

We move all terms to the left:

73-(3x+(x+3)+(4x-2))=0



We calculate terms in parentheses: -(3x+(x+3)+(4x-2)), so:

3x+(x+3)+(4x-2)

We get rid of parentheses

3x+x+4x+3-2

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We get rid of parentheses

-8x-1+73=0

We add all the numbers together, and all the variables

-8x+72=0

We move all terms containing x to the left, all other terms to the right

-8x=-72

x=-72/-8

x=+9

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