7/8v+6/5v=-1577/246

Solution for 7/8v+6/5v=-1577/246 equation:

7/8v+6/5v=-1577/246

We move all terms to the left:

7/8v+6/5v-(-1577/246)=0


Domain of the equation: 8v!=0

v!=0/8

v!=0

v∈R



Domain of the equation: 5v!=0

v!=0/5

v!=0

v∈R


We get rid of parentheses

7/8v+6/5v+1577/246=0

We calculate fractions


315400v^2/19680v^2+17220v/19680v^2+23616v/19680v^2=0

We multiply all the terms by the denominator


315400v^2+17220v+23616v=0

We add all the numbers together, and all the variables

315400v^2+40836v=0

a = 315400; b = 40836; c = 0;
Δ = b2-4ac
Δ = 408362-4·315400·0
Δ = 1667578896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1667578896}=40836$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40836)-40836}{2*315400}=\frac{-81672}{630800}
=-123/950
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40836)+40836}{2*315400}=\frac{0}{630800}
=0
$