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2x-3(3-4x)=4(x-5)-9
We move all terms to the left:
2x-3(3-4x)-(4(x-5)-9)=0
We add all the numbers together, and all the variables
2x-3(-4x+3)-(4(x-5)-9)=0
We multiply parentheses
2x+12x-(4(x-5)-9)-9=0
We calculate terms in parentheses: -(4(x-5)-9), so:We add all the numbers together, and all the variables
4(x-5)-9
We multiply parentheses
4x-20-9
We add all the numbers together, and all the variables
4x-29
Back to the equation:
-(4x-29)
14x-(4x-29)-9=0
We get rid of parentheses
14x-4x+29-9=0
We add all the numbers together, and all the variables
10x+20=0
We move all terms containing x to the left, all other terms to the right
10x=-20
x=-20/10
x=-2
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