7/5x+7/10x=48/15

Solution for 7/5x+7/10x=48/15 equation:

7/5x+7/10x=48/15

We move all terms to the left:

7/5x+7/10x-(48/15)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

7/5x+7/10x-(+48/15)=0

We get rid of parentheses

7/5x+7/10x-48/15=0

We calculate fractions


(-2400x^2)/750x^2+1050x/750x^2+525x/750x^2=0

We multiply all the terms by the denominator


(-2400x^2)+1050x+525x=0

We add all the numbers together, and all the variables

(-2400x^2)+1575x=0

We get rid of parentheses

-2400x^2+1575x=0

a = -2400; b = 1575; c = 0;
Δ = b2-4ac
Δ = 15752-4·(-2400)·0
Δ = 2480625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2480625}=1575$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1575)-1575}{2*-2400}=\frac{-3150}{-4800}
=21/32
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1575)+1575}{2*-2400}=\frac{0}{-4800}
=0
$