5z+12=(2z+6)+4z-3

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Solution for 5z+12=(2z+6)+4z-3 equation:



5z+12=(2z+6)+4z-3
We move all terms to the left:
5z+12-((2z+6)+4z-3)=0
We calculate terms in parentheses: -((2z+6)+4z-3), so:
(2z+6)+4z-3
We add all the numbers together, and all the variables
4z+(2z+6)-3
We get rid of parentheses
4z+2z+6-3
We add all the numbers together, and all the variables
6z+3
Back to the equation:
-(6z+3)
We get rid of parentheses
5z-6z-3+12=0
We add all the numbers together, and all the variables
-1z+9=0
We move all terms containing z to the left, all other terms to the right
-z=-9
z=-9/-1
z=+9

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