2(y+1)=-6(2y-2)+6y

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Solution for 2(y+1)=-6(2y-2)+6y equation: 



2(y+1)=-6(2y-2)+6y

We move all terms to the left:

2(y+1)-(-6(2y-2)+6y)=0

We multiply parentheses

2y-(-6(2y-2)+6y)+2=0



We calculate terms in parentheses: -(-6(2y-2)+6y), so:

-6(2y-2)+6y

We add all the numbers together, and all the variables

6y-6(2y-2)

We multiply parentheses

6y-12y+12

We add all the numbers together, and all the variables

-6y+12

Back to the equation:

-(-6y+12)



We get rid of parentheses

2y+6y-12+2=0

We add all the numbers together, and all the variables

8y-10=0

We move all terms containing y to the left, all other terms to the right

8y=10

y=10/8

y=1+1/4

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