2(x-5)-5(x-2)=x+8-(x-4)

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Solution for 2(x-5)-5(x-2)=x+8-(x-4) equation: 



2(x-5)-5(x-2)=x+8-(x-4)

We move all terms to the left:

2(x-5)-5(x-2)-(x+8-(x-4))=0

We multiply parentheses

2x-5x-(x+8-(x-4))-10+10=0



We calculate terms in parentheses: -(x+8-(x-4)), so:

x+8-(x-4)

determiningTheFunctionDomain
x-(x-4)+8

We get rid of parentheses

x-x+4+8

We add all the numbers together, and all the variables

12

Back to the equation:

-(12)



We add all the numbers together, and all the variables

-3x-12=0

We move all terms containing x to the left, all other terms to the right

-3x=12

x=12/-3

x=-4

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