2x+6=11x-(1/8)

Solution for 2x+6=11x-(1/8) equation:

2x+6=11x-(1/8)

We move all terms to the left:

2x+6-(11x-(1/8))=0

We add all the numbers together, and all the variables

2x-(11x-(+1/8))+6=0

We multiply all the terms by the denominator


2x*8))-(11x-(+1+6*8))=0

We add all the numbers together, and all the variables

2x*8))-(11x-49)=0

Wy multiply elements

16x^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{32}=0$