7/5x+4/10x=36/15

Solution for 7/5x+4/10x=36/15 equation:

7/5x+4/10x=36/15

We move all terms to the left:

7/5x+4/10x-(36/15)=0


Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



Domain of the equation: 10x!=0

x!=0/10

x!=0

x∈R


We add all the numbers together, and all the variables

7/5x+4/10x-(+36/15)=0

We get rid of parentheses

7/5x+4/10x-36/15=0

We calculate fractions


(-1800x^2)/750x^2+1050x/750x^2+300x/750x^2=0

We multiply all the terms by the denominator


(-1800x^2)+1050x+300x=0

We add all the numbers together, and all the variables

(-1800x^2)+1350x=0

We get rid of parentheses

-1800x^2+1350x=0

a = -1800; b = 1350; c = 0;
Δ = b2-4ac
Δ = 13502-4·(-1800)·0
Δ = 1822500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1822500}=1350$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1350)-1350}{2*-1800}=\frac{-2700}{-3600}
=3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1350)+1350}{2*-1800}=\frac{0}{-3600}
=0
$