5(4+r)=2/(40+10r)

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Solution for 5(4+r)=2/(40+10r) equation:



5(4+r)=2/(40+10r)
We move all terms to the left:
5(4+r)-(2/(40+10r))=0
Domain of the equation: (40+10r))!=0
We move all terms containing r to the left, all other terms to the right
10r)!=-40
r!=-40/1
r!=-40
r∈R
We add all the numbers together, and all the variables
5(r+4)-(2/(10r+40))=0
We multiply parentheses
5r-(2/(10r+40))+20=0
We multiply all the terms by the denominator
5r*(10r+40))-(2+20*(10r+40))=0
We multiply parentheses
5r*(10r+40))-(2+200r+=0
We add all the numbers together, and all the variables
200r+5r*(10r+40))-(2=0

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