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7/4x+7/4x+x+x=66
We move all terms to the left:
7/4x+7/4x+x+x-(66)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
2x+7/4x+7/4x-66=0
We multiply all the terms by the denominator
2x*4x-66*4x+7+7=0
We add all the numbers together, and all the variables
2x*4x-66*4x+14=0
Wy multiply elements
8x^2-264x+14=0
a = 8; b = -264; c = +14;
Δ = b2-4ac
Δ = -2642-4·8·14
Δ = 69248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{69248}=\sqrt{64*1082}=\sqrt{64}*\sqrt{1082}=8\sqrt{1082}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-264)-8\sqrt{1082}}{2*8}=\frac{264-8\sqrt{1082}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-264)+8\sqrt{1082}}{2*8}=\frac{264+8\sqrt{1082}}{16} $
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