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(3x-6)(2x-5)=0
We multiply parentheses ..
(+6x^2-15x-12x+30)=0
We get rid of parentheses
6x^2-15x-12x+30=0
We add all the numbers together, and all the variables
6x^2-27x+30=0
a = 6; b = -27; c = +30;
Δ = b2-4ac
Δ = -272-4·6·30
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-3}{2*6}=\frac{24}{12} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+3}{2*6}=\frac{30}{12} =2+1/2 $
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