0.003x2-0.002x-0.005=0

Solution for 0.003x2-0.002x-0.005=0 equation:

0.003x^2-0.002x-0.005=0

a = 0.003; b = -0.002; c = -0.005;
Δ = b2-4ac
Δ = -0.0022-4·0.003·(-0.005)
Δ = 6.4E-5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.002)-\sqrt{6.4E-5}}{2*0.003}=\frac{0.002-\sqrt{6.4E-5}}{0.006}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.002)+\sqrt{6.4E-5}}{2*0.003}=\frac{0.002+\sqrt{6.4E-5}}{0.006}
$