7/4x+4/8x=50/12

Solution for 7/4x+4/8x=50/12 equation:

7/4x+4/8x=50/12

We move all terms to the left:

7/4x+4/8x-(50/12)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We add all the numbers together, and all the variables

7/4x+4/8x-(+50/12)=0

We get rid of parentheses

7/4x+4/8x-50/12=0

We calculate fractions


(-12800x^2)/384x^2+672x/384x^2+192x/384x^2=0

We multiply all the terms by the denominator


(-12800x^2)+672x+192x=0

We add all the numbers together, and all the variables

(-12800x^2)+864x=0

We get rid of parentheses

-12800x^2+864x=0

a = -12800; b = 864; c = 0;
Δ = b2-4ac
Δ = 8642-4·(-12800)·0
Δ = 746496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{746496}=864$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(864)-864}{2*-12800}=\frac{-1728}{-25600}
=27/400
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(864)+864}{2*-12800}=\frac{0}{-25600}
=0
$